Question

on a recent biology midterm, the class mean was 67 with a standard deviation of 2.7. calculate the z - score (to 4 decimal places) for a person who received score of 71.
z - score for biology midterm:
the same person also took a midterm in their marketing course and received a score of 75. the class mean was 72 with a standard deviation of 6. calculate the z - score (to 4 decimal places).
z - score for marketing midterm:
which test did the person perform better on compared to the rest of the class? select an answer

Explanation:

Step1: Recall z - score formula

The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x$ is the individual score, $\mu$ is the mean, and $\sigma$ is the standard deviation.

Step2: Calculate z - score for biology midterm

Given $x = 71$, $\mu=67$, $\sigma = 2.7$. Substitute into the formula: $z_1=\frac{71 - 67}{2.7}=\frac{4}{2.7}\approx1.4815$.

Step3: Calculate z - score for marketing midterm

Given $x = 75$, $\mu = 72$, $\sigma=6$. Substitute into the formula: $z_2=\frac{75 - 72}{6}=\frac{3}{6}=0.5000$.

Step4: Compare z - scores

Since $1.4815>0.5000$, the person performed better on the biology mid - term compared to the rest of the class.

Answer:

z - score for Biology Midterm: 1.4815
z - score for Marketing Midterm: 0.5000
Which test did the person perform better on compared to the rest of the class? Biology Midterm