Question

required information .
a 5-kg block being pushed across a table by a force $p$ has an acceleration of $7\\,\text{m/s}^2$.
note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.

if the magnitude of $p$ is 38 n, what is the magnitude of the frictional force acting upon the block?
the magnitude of the frictional force acting upon the block is $\boldsymbol{\square}$ n.

Explanation:

Step1: Recall Newton's second law

Newton's second law states $\sum F = ma$, where $\sum F$ is net force, $m$ is mass, $a$ is acceleration.

Step2: Define net force

Net force is applied force minus friction: $\sum F = P - f$

Step3: Substitute values into formula

Substitute $P=38\ \text{N}$, $m=5\ \text{kg}$, $a=7\ \text{m/s}^2$:
$38 - f = 5 \times 7$

Step4: Solve for frictional force f

Calculate $5 \times 7 = 35$, then rearrange:
$f = 38 - 35$

Answer:

$3$