Question

review the expressions for $j(x)$ and $j(-x)$
$j(x)=\frac{220}{x^3}$
$j(-x)=\frac{220}{(-x)^3}$
which statement describes the symmetry of $j(x)$?
○ $j(x)$ is an odd function.
○ $j(x)$ is an even function.
○ $j(x)$ is both an even and an odd function.
○ $j(x)$ is neither an even nor an odd function.

Explanation:

Step1: Simplify $j(-x)$

$j(-x)=\frac{220}{(-x)^3}=\frac{220}{-x^3}=-\frac{220}{x^3}$

Step2: Compare to $-j(x)$

$-j(x)=-\frac{220}{x^3}$

Step3: Match function symmetry rule

Since $j(-x) = -j(x)$, this fits the definition of an odd function.

Answer:

j(x) is an odd function.