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review questions 1. what is a coulomb? 2. what is an amp? 3. define voltage. 4. define ohm. 5. define watt. 6. an electric heating element has a resistance of 16ω and is connected to a voltage of 120 v. how much current will flow in this circuit? 7. how many watts of heat are being produced by the heating element in question 6? 8. a 240 - v circuit has a current flow of 20 a. how much resistance is connected to the circuit?
- A coulomb is the SI unit of electric charge, equal to the charge transported by a constant current of 1 ampere in 1 second.
- An amp (ampere) is the SI unit of electric current, defined as the constant current that produces a specified force between two parallel conductors.
- Voltage is the electric potential difference between two points, driving electric charge flow.
- An ohm is the SI unit of electrical resistance, the resistance of a conductor with 1 volt across it and 1 ampere flowing through it.
- A watt is the SI unit of electric power, equal to 1 joule of energy per second.
- Use Ohm's Law ($I=\frac{V}{R}$) to find current from voltage and resistance.
- Use power formula ($P=\frac{V^2}{R}$) to calculate heat (power) from voltage and resistance.
- Use Ohm's Law ($R=\frac{V}{I}$) to find resistance from voltage and current.
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- A coulomb is the SI unit of electric charge, equivalent to the charge carried by 1 ampere of current flowing for 1 second.
- An amp (ampere) is the SI unit of electric current, measuring the rate of flow of electric charge.
- Voltage (electric potential difference) is the force that drives electric current through a conductor, measured in volts.
- An ohm is the SI unit of electrical resistance, representing the opposition to electric current flow in a conductor.
- A watt is the SI unit of electric power, measuring the rate at which electrical energy is transferred or used.
6.
Step1: Apply Ohm's Law for current
$I = \frac{V}{R} = \frac{120\ \text{V}}{16\ \Omega} = 7.5\ \text{A}$
Final answer for 6: $7.5\ \text{A}$
7.
Step1: Apply power formula for heat
$P = \frac{V^2}{R} = \frac{(120\ \text{V})^2}{16\ \Omega} = 900\ \text{watts}$
Final answer for 7: $900\ \text{watts}$
8.
Step1: Apply Ohm's Law for resistance
$R = \frac{V}{I} = \frac{240\ \text{V}}{20\ \text{A}} = 12\ \Omega$
Final answer for 8: $12\ \Omega$