Question

review: what does this program print?
a.inside: 1 outside: 2
x = 1
def printsomething(x):
print(\inside:\, x)
print(\outside:\, printsomething(x+1))
b.inside: 2 outside: 1
c.inside: 2 outside: none
d.inside: none outside: none
e.(nothing. it crashes)
join code: 101

Explanation:

Step1: Analyze function execution

When printSomething(x+1) runs, x+1 is 1+1=2, so the function prints "Inside: 2".

Step2: Check function return value

The printSomething function has no explicit return statement, so it automatically returns None.

Step3: Analyze outer print statement

The outer print command outputs "Outside:" followed by the return value of printSomething(x+1), which is None.

Answer:

C. Inside: 2 Outside: None