Question

rewrite \\(\frac{((y + 3)^4)}{((y + 3)^5)}\\) in lowest terms.

Explanation:

Step1: Apply exponent quotient rule

Recall $\frac{x^m}{x^n}=x^{m-n}$. Here $x=(y+3)$, $m=4$, $n=5$.
$\frac{(y+3)^4}{(y+3)^5}=(y+3)^{4-5}$

Step2: Simplify the exponent

Calculate the exponent value.
$(y+3)^{-1}$

Step3: Rewrite to positive exponent

Use $x^{-k}=\frac{1}{x^k}$.
$\frac{1}{y+3}$ (where $y
eq -3$)

Answer:

$\frac{1}{y+3}$