Question

round all answers to the nearest tenth of a meter. how far did player a throw the ball? 8.9 m how far did player b throw the ball? 17.5 m how far would player a have to throw the ball to throw it to player c directly?

Explanation:

1. Assume coordinates of players:

• Let's assume player A has coordinates \((x_1,y_1)\) and player C has coordinates \((x_2,y_2)\). Since the picture is not clear - enough to get the exact coordinates, we'll use the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\).

1. If we assume player A is at \((4,4)\) and player C is at \((16,7)\) (estimating from the graph):

• First, find the difference in \(x\) - coordinates: \(\Delta x=x_2 - x_1=16 - 4 = 12\).
• Then, find the difference in \(y\) - coordinates: \(\Delta y=y_2 - y_1=7 - 4 = 3\).
• Now, use the distance formula \(d=\sqrt{\Delta x^{2}+\Delta y^{2}}=\sqrt{12^{2}+3^{2}}=\sqrt{144 + 9}=\sqrt{153}\).
• Calculate \(\sqrt{153}\approx12.4\).

Step 1: Identify coordinates

Assume player A \((4,4)\) and player C \((16,7)\)

Step 2: Calculate \(\Delta x\) and \(\Delta y\)

\(\Delta x = 16 - 4=12\), \(\Delta y=7 - 4 = 3\)

Step 3: Apply distance formula

\(d=\sqrt{12^{2}+3^{2}}=\sqrt{144 + 9}=\sqrt{153}\approx12.4\)

Answer:

12.4 m