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if round is dominant to wrinkled and yellow is dominant to green, which…

Question

if round is dominant to wrinkled and yellow is dominant to green, which of the following offspring have wrinkled and yellow phenotypes? tap on the rectangle hotspot to mark as correct.

Explanation:

Step1: Recall Dominant/Recessive Traits

Round (R) and yellow (Y) are dominant; wrinkled (r) and green (y) are recessive. So wrinkled and green phenotype needs \(rr\) (for wrinkled) and \(yy\) (for green), i.e., genotype \(rryy\).

Step2: Analyze Punnett Square Cells

Check each cell:

  • \(RRYY\), \(RRYy\), \(RrYY\), \(RrYy\) have dominant traits (round, yellow) or some dominant.
  • The cells with \(rryy\) (if present) would be wrinkled (rr) and green (yy). Looking at the Punnett square, the bottom - left cells (last row, first column and maybe others? Wait, let's re - check. Wait, the columns are \(RY\), \(Ry\), \(rY\), \(ry\) (wait, no, the top row of the Punnett square (gametes) and left column. Wait, the genotype for wrinkled (rr) and green (yy) is \(rryy\). So we need to find the cell with \(rryy\). Looking at the Punnett square, the cells with \(rryy\) (assuming the gametes are such that when we cross, the \(rryy\) is formed when both parents contribute \(ry\) gametes. Wait, maybe the user's Punnett square has \(rryy\) in the bottom - left (last row, first column? Wait, no, let's see the labels. The left column gametes: \(RY\), \(Ry\), \(rY\), \(ry\) (maybe) and top row gametes: \(RY\), \(Ry\), \(rY\), \(ry\). Then \(rryy\) is when both are \(ry\), so the cell at the intersection of \(ry\) (left) and \(ry\) (top). So we need to identify that cell.

Answer:

The cell with genotype \(rryy\) (the one with wrinkled and green phenotype, so in the Punnett square, the bottom - left most cell or the cell where both gametes are \(ry\)) is the correct one. (Assuming the Punnett square has \(rryy\) in the last row, first column or similar, the cell with \(rryy\) is the offspring with wrinkled (rr) and green (yy) phenotype.)