QUESTION IMAGE
Question
ruler quiz vii
part i
put the appropriate measurement to match each letter. be sure to reduce
- b = ____ 2. c = __ 3. d = __ 4. e = __ 5. f = ____
- g = ____ 7. h = __ 8. i = __ 9. j = __ 10. k = ____
- l = ____ 12. m = __ 13. n = __ 14. o = __ 15. p = ____
- ______
- ______
- ______
- ______
- ______
To solve the ruler measurement problems, we analyze each part:
Part I (Top Ruler, A=0, 1 and 2 are in inches, assuming each inch has 16 fractions):
- B: From A (0) to B, count the ticks. Each small tick is $\frac{1}{16}$ inch. B is at 2 ticks: $\frac{2}{16} = \frac{1}{8}$ inch.
- C: 5 ticks from A: $\frac{5}{16}$ inch.
- D: 8 ticks from A: $\frac{8}{16} = \frac{1}{2}$ inch.
- E: 12 ticks from A: $\frac{12}{16} = \frac{3}{4}$ inch.
- F: 15 ticks from A: $\frac{15}{16}$ inch.
- G: 1 inch + 1 tick: $1 + \frac{1}{16} = \frac{17}{16}$ inch.
- H: 1 inch + 4 ticks: $1 + \frac{4}{16} = 1\frac{1}{4}$ inch.
- I: 1 inch + 7 ticks: $1 + \frac{7}{16} = \frac{23}{16}$ inch.
- J: 1 inch + 8 ticks: $1 + \frac{8}{16} = 1\frac{1}{2}$ inch.
- K: 1 inch + 11 ticks: $1 + \frac{11}{16} = \frac{27}{16}$ inch.
- L: 1 inch + 12 ticks: $1 + \frac{12}{16} = 1\frac{3}{4}$ inch.
- M: 1 inch + 14 ticks: $1 + \frac{14}{16} = 1\frac{7}{8}$ inch.
- N: 1 inch + 15 ticks: $1 + \frac{15}{16} = \frac{31}{16}$ inch.
- O: 2 inches: $2$ inch.
- P: 2 inches + 1 tick: $2 + \frac{1}{16} = \frac{33}{16}$ inch.
Part II (Bottom Rulers, assuming units are centimeters, each cm has 10 mm):
- Arrow at 3.7 cm (37 mm): $3.7$ cm or $\frac{37}{10}$ cm.
- Arrow at 3.2 cm (32 mm): $3.2$ cm or $\frac{16}{5}$ cm.
- Arrow at 0.9 cm (9 mm): $0.9$ cm or $\frac{9}{10}$ cm.
- Arrow at 5.3 cm (53 mm): $5.3$ cm or $\frac{53}{10}$ cm.
- Arrow at 4.3 cm (43 mm): $4.3$ cm or $\frac{43}{10}$ cm.
Final Answers (Part I, 1–15):
- $\boldsymbol{\frac{1}{8}}$ inch
- $\boldsymbol{\frac{5}{16}}$ inch
- $\boldsymbol{\frac{1}{2}}$ inch
- $\boldsymbol{\frac{3}{4}}$ inch
- $\boldsymbol{\frac{15}{16}}$ inch
- $\boldsymbol{\frac{17}{16}}$ inch
- $\boldsymbol{1\frac{1}{4}}$ inch
- $\boldsymbol{\frac{23}{16}}$ inch
- $\boldsymbol{1\frac{1}{2}}$ inch
- $\boldsymbol{\frac{27}{16}}$ inch
- $\boldsymbol{1\frac{3}{4}}$ inch
- $\boldsymbol{1\frac{7}{8}}$ inch
- $\boldsymbol{\frac{31}{16}}$ inch
- $\boldsymbol{2}$ inch
- $\boldsymbol{\frac{33}{16}}$ inch
Final Answers (Part II, 16–20):
- $\boldsymbol{3.7}$ cm (or $\boldsymbol{\frac{37}{10}}$ cm)
- $\boldsymbol{3.2}$ cm (or $\boldsymbol{\frac{16}{5}}$ cm)
- $\boldsymbol{0.9}$ cm (or $\boldsymbol{\frac{9}{10}}$ cm)
- $\boldsymbol{5.3}$ cm (or $\boldsymbol{\frac{53}{10}}$ cm)
- $\boldsymbol{4.3}$ cm (or $\boldsymbol{\frac{43}{10}}$ cm)
(Note: If the top ruler is in sixteenths of an inch, and the bottom in millimeters/centimeters, adjust based on the actual scale. The above assumes standard inch (16ths) and centimeter (10ths) scales.)
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To solve the ruler measurement problems, we analyze each part:
Part I (Top Ruler, A=0, 1 and 2 are in inches, assuming each inch has 16 fractions):
- B: From A (0) to B, count the ticks. Each small tick is $\frac{1}{16}$ inch. B is at 2 ticks: $\frac{2}{16} = \frac{1}{8}$ inch.
- C: 5 ticks from A: $\frac{5}{16}$ inch.
- D: 8 ticks from A: $\frac{8}{16} = \frac{1}{2}$ inch.
- E: 12 ticks from A: $\frac{12}{16} = \frac{3}{4}$ inch.
- F: 15 ticks from A: $\frac{15}{16}$ inch.
- G: 1 inch + 1 tick: $1 + \frac{1}{16} = \frac{17}{16}$ inch.
- H: 1 inch + 4 ticks: $1 + \frac{4}{16} = 1\frac{1}{4}$ inch.
- I: 1 inch + 7 ticks: $1 + \frac{7}{16} = \frac{23}{16}$ inch.
- J: 1 inch + 8 ticks: $1 + \frac{8}{16} = 1\frac{1}{2}$ inch.
- K: 1 inch + 11 ticks: $1 + \frac{11}{16} = \frac{27}{16}$ inch.
- L: 1 inch + 12 ticks: $1 + \frac{12}{16} = 1\frac{3}{4}$ inch.
- M: 1 inch + 14 ticks: $1 + \frac{14}{16} = 1\frac{7}{8}$ inch.
- N: 1 inch + 15 ticks: $1 + \frac{15}{16} = \frac{31}{16}$ inch.
- O: 2 inches: $2$ inch.
- P: 2 inches + 1 tick: $2 + \frac{1}{16} = \frac{33}{16}$ inch.
Part II (Bottom Rulers, assuming units are centimeters, each cm has 10 mm):
- Arrow at 3.7 cm (37 mm): $3.7$ cm or $\frac{37}{10}$ cm.
- Arrow at 3.2 cm (32 mm): $3.2$ cm or $\frac{16}{5}$ cm.
- Arrow at 0.9 cm (9 mm): $0.9$ cm or $\frac{9}{10}$ cm.
- Arrow at 5.3 cm (53 mm): $5.3$ cm or $\frac{53}{10}$ cm.
- Arrow at 4.3 cm (43 mm): $4.3$ cm or $\frac{43}{10}$ cm.
Final Answers (Part I, 1–15):
- $\boldsymbol{\frac{1}{8}}$ inch
- $\boldsymbol{\frac{5}{16}}$ inch
- $\boldsymbol{\frac{1}{2}}$ inch
- $\boldsymbol{\frac{3}{4}}$ inch
- $\boldsymbol{\frac{15}{16}}$ inch
- $\boldsymbol{\frac{17}{16}}$ inch
- $\boldsymbol{1\frac{1}{4}}$ inch
- $\boldsymbol{\frac{23}{16}}$ inch
- $\boldsymbol{1\frac{1}{2}}$ inch
- $\boldsymbol{\frac{27}{16}}$ inch
- $\boldsymbol{1\frac{3}{4}}$ inch
- $\boldsymbol{1\frac{7}{8}}$ inch
- $\boldsymbol{\frac{31}{16}}$ inch
- $\boldsymbol{2}$ inch
- $\boldsymbol{\frac{33}{16}}$ inch
Final Answers (Part II, 16–20):
- $\boldsymbol{3.7}$ cm (or $\boldsymbol{\frac{37}{10}}$ cm)
- $\boldsymbol{3.2}$ cm (or $\boldsymbol{\frac{16}{5}}$ cm)
- $\boldsymbol{0.9}$ cm (or $\boldsymbol{\frac{9}{10}}$ cm)
- $\boldsymbol{5.3}$ cm (or $\boldsymbol{\frac{53}{10}}$ cm)
- $\boldsymbol{4.3}$ cm (or $\boldsymbol{\frac{43}{10}}$ cm)
(Note: If the top ruler is in sixteenths of an inch, and the bottom in millimeters/centimeters, adjust based on the actual scale. The above assumes standard inch (16ths) and centimeter (10ths) scales.)