Question

a seagull is landing on a beach. the seagull weighs 18 newtons. as the seagull lands, it expands its wings, creating a force of air resistance of 25 newtons.
describe the seagulls motion.
the seagull is while experiencing a net force .
so, the magnitude of the seagulls velocity is .

Explanation:

Step1: Define force directions

Let upward be positive. Weight $F_g = -18\ \text{N}$ (downward), air resistance $F_{air} = 25\ \text{N}$ (upward).

Step2: Calculate net force

Net force $F_{net} = F_{air} + F_g$
$F_{net} = 25\ \text{N} + (-18\ \text{N}) = 7\ \text{N}$

Step3: Relate force to motion

Net force is upward, opposite to downward motion.

Step4: Relate force to velocity change

Upward net force slows downward motion.

Answer:

The seagull is decelerating (slowing down) while experiencing a net force of 7 newtons upward.
So, the magnitude of the seagull's velocity is decreasing.