Question

section 7.2 homework
score: 5/14 answered: 5/14
question 6
a normal distribution has a mean of 95 and a standard deviation of 10. find the z - score for a data value of 132.
round to two decimal places

Explanation:

Step1: Recall z - score formula

The formula for the z - score is $z=\frac{x-\mu}{\sigma}$, where $x$ is the data value, $\mu$ is the mean, and $\sigma$ is the standard deviation.

Step2: Identify values

We are given that $\mu = 95$, $\sigma=10$, and $x = 132$.

Step3: Substitute values into formula

$z=\frac{132 - 95}{10}=\frac{37}{10}=3.70$

Answer:

$3.70$