Question

section 5.2 homework
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the table summarizes results from 984 pedestrian deaths that were caused by au
pedestrian deaths
driver intoxicated? pedestrian intoxicated?
yes no
yes 60 69
no 252 603
if one of the pedestrian deaths is randomly selected, find the probability that the intoxicated or the driver was not intoxicated. please enter a decimal to 4 decimal
probability = 0.9390 ×

Explanation:

Step1: Calculate total number of cases

The total number of pedestrian - deaths is \(60 + 69+252 + 603=984\).

Step2: Calculate number of favorable cases

Let \(A\) be the event that the pedestrian was intoxicated and \(B\) be the event that the driver was not intoxicated.
The number of cases where the pedestrian was intoxicated is \(60 + 252=312\).
The number of cases where the driver was not intoxicated is \(252+603 = 855\).
The number of cases where the pedestrian was intoxicated and the driver was not intoxicated is \(252\).
Using the formula \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\), we have \(n(A\cup B)=312 + 855-252=915\).

Step3: Calculate the probability

The probability \(P=\frac{n(A\cup B)}{n(\text{total})}=\frac{915}{984}\approx0.9390\).

Answer:

\(0.9390\)