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Question
section 5.1 homework
score: 7/17 answered: 7/17
question 8
a bag of m&ms has 5 red, 6 green, 2 blue, and 4 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places)
a) a yellow?
b) a blue or green?
c) an orange?
Step1: Calculate total number of marbles
$5 + 6+2 + 4=17$
Step2: Calculate probability of picking a yellow marble
The number of yellow marbles is 4. Probability formula is $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{yellow})=\frac{4}{17}\approx0.2353$
Step3: Calculate probability of picking a blue or green marble
Number of blue marbles is 2 and green is 6. So number of favorable outcomes for blue or green is $2 + 6=8$. Then $P(\text{blue or green})=\frac{8}{17}\approx0.4706$
Step4: Calculate probability of picking an orange marble
There are 0 orange marbles. So $P(\text{orange})=\frac{0}{17}=0$
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a) $0.2353$
b) $0.4706$
c) $0$