Question

select all the equations where m = 4 is a solution.
choose 3 answers:
a 13 = 9 + m
b 7 - m = 3
c 15 = 11m
d 5 = m + 2
e 20 ÷ m = 5

Explanation:

Step1: Check Option A

Substitute \( m = 4 \) into \( 13 = 9 + m \).
Right - hand side: \( 9+4=13 \), which is equal to the left - hand side. So \( m = 4 \) is a solution for option A.

Step2: Check Option B

Substitute \( m = 4 \) into \( 7 - m=3 \).
Left - hand side: \( 7 - 4 = 3 \), which is equal to the right - hand side. So \( m = 4 \) is a solution for option B.

Step3: Check Option C

Substitute \( m = 4 \) into \( 15 = 11m \).
Right - hand side: \( 11\times4 = 44
eq15 \). So \( m = 4 \) is not a solution for option C.

Step4: Check Option D

Substitute \( m = 4 \) into \( 5=m + 2 \).
Right - hand side: \( 4+2=6
eq5 \). Wait, there is a mistake here. Wait, if \( m = 3 \), \( 3 + 2=5 \). Wait, let's re - check. Wait, the equation is \( 5=m + 2 \). Solving for \( m \), we get \( m=5 - 2=3 \). So \( m = 4 \) is not a solution for option D. Wait, maybe I made a mistake. Wait, the original problem's option D: \( 5=m + 2 \). If \( m = 3 \), then \( 3+2 = 5 \). So \( m = 4 \) is not a solution. Wait, let's check option E.

Step5: Check Option E

Substitute \( m = 4 \) into \( 20\div m = 5 \).
Left - hand side: \( 20\div4=5 \), which is equal to the right - hand side. So \( m = 4 \) is a solution for option E.

Wait, there is a mistake in my previous step for option D. Let's re - check the options. Wait, maybe I misread the options. Let's list all options again:

Option A: \( 13=9 + m \), when \( m = 4 \), \( 9 + 4=13 \), correct.

Option B: \( 7 - m=3 \), when \( m = 4 \), \( 7-4 = 3 \), correct.

Option C: \( 15 = 11m \), \( 11\times4 = 44
eq15 \), incorrect.

Option D: \( 5=m + 2 \), \( m=5 - 2 = 3
eq4 \), incorrect. Wait, but the problem says to choose 3 answers. So maybe I made a mistake. Wait, maybe option D is \( 5=m - 2 \)? No, the user's image shows \( 5=m + 2 \). Wait, maybe there is another option. Wait, let's check again.

Wait, maybe I misread option D. Let's see: the user's image has option D as \( 5=m + 2 \), option E as \( 20\div m = 5 \). Wait, maybe there is a typo, or maybe I missed an option. Wait, let's check option A, B, and E. But the problem says to choose 3 answers. Wait, maybe option D is correct? Wait, if \( m = 3 \), \( 3+2 = 5 \), so \( m = 4 \) gives \( 4 + 2=6
eq5 \). So D is incorrect. Wait, maybe the original problem has a different option. Wait, maybe option D is \( 5=m - 2 \)? No, the user's image shows \( 5=m + 2 \).

Wait, maybe I made a mistake in option D. Wait, let's check the options again. The options are:

A. \( 13 = 9 + m \)

B. \( 7 - m=3 \)

C. \( 15 = 11m \)

D. \( 5=m + 2 \)

E. \( 20\div m = 5 \)

Wait, let's solve each equation for \( m \):

A: \( m=13 - 9=4 \), so \( m = 4 \) is a solution.

B: \( m=7 - 3 = 4 \), so \( m = 4 \) is a solution.

C: \( m=\frac{15}{11}
eq4 \), not a solution.

D: \( m=5 - 2 = 3
eq4 \), not a solution.

E: \( m=\frac{20}{5}=4 \), so \( m = 4 \) is a solution.

But the problem says to choose 3 answers. So maybe there is a mistake in my analysis. Wait, maybe option D is \( 5=m - 2 \)? If so, \( m=5 + 2 = 7
eq4 \). No. Wait, maybe option D is \( 5=m\times2 \)? No, the user's image shows \( 5=m + 2 \).

Wait, maybe the user made a typo, but according to the given options, the correct answers are A, B, and E. But the problem says to choose 3 answers. So A, B, E.

Answer:

A. \( 13 = 9 + m \), B. \( 7 - m = 3 \), E. \( 20\div m = 5 \)