Question

simplify the following expression completely. write yo
\frac{(x^{3})^{9}}{(x^{3})^{-6}} =

Explanation:

Step1: Use exponent rule \((a^m)^n = a^{m \cdot n}\)

For numerator: \((x^3)^9 = x^{3 \times 9} = x^{27}\)
For denominator: \((x^3)^{-6} = x^{3 \times (-6)} = x^{-18}\)

Step2: Use division rule \(a^m \div a^n = a^{m - n}\)

\(\frac{x^{27}}{x^{-18}} = x^{27 - (-18)} = x^{27 + 18} = x^{45}\)

Answer:

\(x^{45}\)