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situation 6: create a new, different combination, with as many people p…

Question

situation 6: create a new, different combination, with as many people possible, that results in no motion. net force =0
different amounts of people with no motion

draw vectors (bigger for larger force) | predicted movement (none, left, right) | actual movement (none, left, right) | sum of forces (n) (0, #-left, #-right)
--- | --- | --- | ---
area with cart, ropes, and fields: force left = ?, force right = ?, sum of forces = ? | | |

Explanation:

Step1: Assign equal force values

Assume each person pulls with 1 N. Let left force = 5 N (5 people), right force = 5 N (5 people).

Step2: Calculate net force

Net force = $F_{\text{right}} - F_{\text{left}} = 5 - 5 = 0$ N

Step3: Predict movement

Net force = 0, so no movement.

Step4: Fill table values

Match forces and movement to table columns.

Answer:

Draw vectors (bigger for larger force)Predicted MovementActual MovementSum of Forces (N) (0, #-left, #-right)

(Note: You can also use higher equal numbers like 6 left and 6 right, as long as the total left and right forces are equal to get a net force of 0.)