Question

solve ( v^2 = -81 ), where ( v ) is a real number. simplify your answer as much as possible. if there is more than one solution, separate them with commas. if there is no solution, click on
o solution\. ( v = )

Explanation:

Step1: Recall the property of squares of real numbers

For any real number \( v \), the square of \( v \), i.e., \( v^{2} \), is always non - negative. That is, if \( v\in\mathbb{R} \), then \( v^{2}\geq0 \).

Step2: Analyze the given equation

We are given the equation \( v^{2}=- 81 \). But we know that the square of a real number cannot be negative. Since \(-81<0\), there is no real number \( v \) that satisfies the equation \( v^{2}=-81 \).

Answer:

No solution