QUESTION IMAGE
Question
solve for x in the equation $x^2 + 20x + 100 = 36$. $\bigcirc$ $x = -16$ or $x = -4$ $\bigcirc$ $x = -10$ $\bigcirc$ $x = -8$ $\bigcirc$ $x = 4$ or $x = 16$
Step1: Rewrite left side as square
$x^2 + 20x + 100 = (x+10)^2$
Equation becomes: $(x+10)^2 = 36$
Step2: Take square roots of both sides
$x+10 = \pm\sqrt{36}$
$x+10 = \pm6$
Step3: Solve for x (case 1)
$x+10 = 6$
$x = 6 - 10 = -4$
Step4: Solve for x (case 2)
$x+10 = -6$
$x = -6 - 10 = -16$
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$x=-16$ or $x=-4$