Question

solve the following system of equations.
$5x + 4y = 5$
$5x + 8y = 25$
$x = \square$
$y = \square$

Explanation:

Step1: Subtract first equation from second

$(5x + 8y) - (5x + 4y) = 25 - 5$
$4y = 20$

Step2: Solve for $y$

$y = \frac{20}{4} = 5$

Step3: Substitute $y=5$ into first equation

$5x + 4(5) = 5$
$5x + 20 = 5$

Step4: Solve for $x$

$5x = 5 - 20 = -15$
$x = \frac{-15}{5} = -3$

Answer:

$x = -3$
$y = 5$