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solve for x to the nearest tenth.

Question

solve for x to the nearest tenth.

Explanation:

Step1: Visualize right triangle offset

If we draw a line from the bottom of the shorter vertical side to the longer vertical side, we form a right triangle. The vertical leg is $5 - 3 = 2$, the horizontal leg is 4, and $x$ is the hypotenuse.

Step2: Apply Pythagorean theorem

The Pythagorean theorem states $a^2 + b^2 = c^2$, where $a=2$, $b=4$, $c=x$.
$$x = \sqrt{2^2 + 4^2}$$

Step3: Calculate the value

First compute the squares: $2^2=4$, $4^2=16$. Sum them: $4 + 16 = 20$. Then take the square root: $\sqrt{20} \approx 4.5$

Answer:

4.5