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solve for b.\\(sqrt{14 + b} = 8\\)\\(b = \\square\\)submit

Question

solve for b.\\(sqrt{14 + b} = 8\\)\\(b = \square\\)submit

Explanation:

Step1: Square both sides to eliminate the square root

To get rid of the square root, we square both sides of the equation \(\sqrt{14 + b}=8\). Squaring the left side gives us \(14 + b\) (since \((\sqrt{x})^2=x\) for \(x\geq0\)), and squaring the right side gives us \(8^2 = 64\). So the equation becomes:
\(14 + b=64\)

Step2: Solve for b by subtracting 14 from both sides

We want to isolate \(b\), so we subtract 14 from both sides of the equation \(14 + b = 64\). Subtracting 14 from the left side cancels out the 14, and subtracting 14 from the right side gives \(64-14\).
\(b=64 - 14\)
\(b = 50\)

Answer:

\(50\)