Question

solve the system of equations.
$-10y + 9x = -9$
$10y + 5x = -5$
$x = square$
$y = square$

Explanation:

Step1: Add the two equations

$$(-10y + 9x) + (10y + 5x) = -9 + (-5)$$
Simplify: $14x = -14$

Step2: Solve for $x$

$$x = \frac{-14}{14} = -1$$

Step3: Substitute $x=-1$ into second equation

$$10y + 5(-1) = -5$$
Simplify: $10y - 5 = -5$

Step4: Solve for $y$

$$10y = -5 + 5 = 0$$
$$y = \frac{0}{10} = 0$$

Answer:

$x = -1$
$y = 0$