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solve for y. \\(\\frac{8}{4y - 8} - 1 = \\frac{2}{y - 2}\\) if there is…

Question

solve for y.
\\(\frac{8}{4y - 8} - 1 = \frac{2}{y - 2}\\)
if there is more than one solution, separate them with commas.
if there is no solution, click on
o solution\.
\\(y = \\)

Explanation:

Step1: Simplify the denominator

Notice that \(4y - 8 = 4(y - 2)\). So the equation \(\frac{8}{4y - 8}-1=\frac{2}{y - 2}\) can be rewritten as \(\frac{8}{4(y - 2)}-1=\frac{2}{y - 2}\). Simplify \(\frac{8}{4(y - 2)}\) to \(\frac{2}{y - 2}\). Now the equation is \(\frac{2}{y - 2}-1=\frac{2}{y - 2}\).

Step2: Subtract \(\frac{2}{y - 2}\) from both sides

Subtract \(\frac{2}{y - 2}\) from both sides of the equation: \(\frac{2}{y - 2}-\frac{2}{y - 2}-1=\frac{2}{y - 2}-\frac{2}{y - 2}\). This simplifies to \(- 1=0\), which is a contradiction. Also, we need to check the domain of the original equation. The denominators \(4y - 8\) and \(y - 2\) cannot be zero, so \(y
eq2\). Since the equation leads to a contradiction, there is no solution.

Answer:

No solution