Question

solve for j.
$j^2 + 11j + 24 = 0$
write each solution as an integer, proper fraction, or improper fraction in simplest form. if there are multiple solutions, separate them with commas.
j =
submit

Explanation:

Step1: Factor the quadratic expression

Find two numbers that multiply to 24 and add to 11. These numbers are 3 and 8, so:
$j^2 + 11j + 24 = (j + 3)(j + 8) = 0$

Step2: Set each factor equal to 0

For the product to be 0, at least one factor is 0:
$j + 3 = 0$ or $j + 8 = 0$

Step3: Solve for j in each equation

For $j + 3 = 0$: $j = -3$
For $j + 8 = 0$: $j = -8$

Answer:

$-8, -3$