QUESTION IMAGE
Question
solving for interior angle measures
what is the m∠acb?
○ 10°
○ 50°
○ 90°
○ 180°
(7x - 20)°
(4x)°
(right angle at a)
Step1: Sum angles of right triangle
$90^\circ + (7x-20)^\circ + (4x)^\circ = 180^\circ$
Step2: Simplify the equation
$90 - 20 + 7x + 4x = 180$
$70 + 11x = 180$
Step3: Solve for $x$
$11x = 180 - 70$
$11x = 110$
$x = 10$
Step4: Calculate $m\angle ACB$
Substitute $x=10$ into $(7x-20)^\circ$:
$7(10) - 20 = 70 - 20 = 50$
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50° (Option: 50°)