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Question
1 sometimes it is helpful to rewrite mixed numbers in a form that includes a fraction greater than 1. use the number line to write the missing numbers. a. $1\frac{3}{6}=\frac{\square}{6}$ b. $2\frac{5}{6}=1\frac{\square}{6}$ c. $2\frac{2}{6}=1\frac{\square}{\square}$ d. $3\frac{1}{6}=\square\frac{\square}{\square}$ 4 what is $3\frac{1}{3}-1\frac{1}{2}$? show your work.
Part 1: Rewriting Mixed Numbers (a - d)
a. \(1\frac{3}{6}=\frac{\square}{6}\)
Step 1: Convert mixed number to improper fraction.
A mixed number \(a\frac{b}{c}=\frac{a\times c + b}{c}\). For \(1\frac{3}{6}\), \(a = 1\), \(b = 3\), \(c = 6\). So \(1\times6+3 = 6 + 3=9\).
Step 1: Subtract 1 from the whole number part.
The whole number part of \(2\frac{5}{6}\) is 2. Subtract 1: \(2 - 1 = 1\). Now, add the fraction part to the remaining whole number's fraction contribution. The fraction part is \(\frac{5}{6}\), and the remaining whole number (1) can be written as \(\frac{6}{6}\). So \(\frac{6}{6}+\frac{5}{6}=\frac{11}{6}\) for the fraction part of the new mixed number.
Step 1: Subtract 1 from the whole number part.
Whole number part: \(2 - 1 = 1\).
Step 2: Add the fraction part and the fraction from the subtracted whole number.
The fraction part of \(2\frac{2}{6}\) is \(\frac{2}{6}\), and 1 (the subtracted whole number) is \(\frac{6}{6}\). So \(\frac{6}{6}+\frac{2}{6}=\frac{8}{6}\).
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