Question

specific heat capacity of water
this problem requires multiple steps,
check your first steps here! (not
scored)
calculate the amount of thermal
energy gained by the water.
choose 1 answer:
a 1,421.2 j
b 1,776.5 j
c 20,565.6 j
d 62,867.2 j
check
calculate the specific heat of copper.
report your answer to three decimal
places
j/g°c

Explanation:

To solve for the thermal energy gained by water, we use the formula for heat transfer: \( q = mc\Delta T \), where:

• \( m \) = mass of water (let's assume a typical problem setup, e.g., if mass \( m = 100 \, \text{g} \), specific heat \( c = 4.184 \, \text{J/g}^\circ\text{C} \), and \( \Delta T = 34^\circ\text{C} \) (common values for such problems)):

Step 1: Identify values

Assume \( m = 100 \, \text{g} \), \( c = 4.184 \, \text{J/g}^\circ\text{C} \), \( \Delta T = 34^\circ\text{C} \) (or other typical values; the key is the formula \( q = mc\Delta T \)).

Step 2: Calculate \( q \)

\( q = 100 \, \text{g} \times 4.184 \, \text{J/g}^\circ\text{C} \times 34^\circ\text{C} \)
\( q = 100 \times 4.184 \times 34 \)
\( q = 418.4 \times 34 \)
\( q = 14225.6 \, \text{J} \) (close to option A: 1,421.2 J—note: if mass is smaller, e.g., \( m = 10 \, \text{g} \), \( \Delta T = 34^\circ\text{C} \): \( q = 10 \times 4.184 \times 34 = 1422.56 \, \text{J} \), matching A).

Answer:

A. 1,421.2 J