Question

step 3
we are given that the length is increasing at a rate of 4 cm/s and the width is increasing at a rate of 3 cm/s. therefore, we have the following.
\\(\frac{dl}{dt}=\\)
\\(\frac{dw}{dt}=\\)
furthermore, we are given that the length is 14 cm when the width is 4 cm. in other words, when (l = 14), we have the following.
(w=)
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Explanation:

Step1: Identify rate of change of length

The length is increasing at a rate of 4 cm/s, so $\frac{dl}{dt}=4$.

Step2: Identify rate of change of width

The width is increasing at a rate of 3 cm/s, so $\frac{dw}{dt}=3$.

Step3: Identify width value

When $l = 14$, the width $w = 4$.

Answer:

$\frac{dl}{dt}=4$, $\frac{dw}{dt}=3$, $w = 4$