Question

1. $y = x^2 + 4x + 3$

$a=$
$b=$
$c=$
$x = \frac{-b}{2a}$
substitute x to find y...
vertex: (, )

Explanation:

Step1: Identify coefficients

Compare $y=x^2+4x+3$ to $y=ax^2+bx+c$:
$a=1$, $b=4$, $c=3$

Step2: Calculate x-coordinate of vertex

Use $x=\frac{-b}{2a}$
$x=\frac{-4}{2\times1}=-2$

Step3: Calculate y-coordinate of vertex

Substitute $x=-2$ into $y=x^2+4x+3$:
$y=(-2)^2+4\times(-2)+3=4-8+3=-1$

Answer:

$a=1$, $b=4$, $c=3$
Vertex: $(-2, -1)$