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QUESTION IMAGE

technology help: the following data shows the number of days (inclusive…

Question

technology help: the following data shows the number of days (inclusive) from a sample of... cars... without using their smartphones. data table frequency table histogram plotting task: drag the bins to the... frequency

Explanation:

Response

To solve this problem, we first need to organize the data and create a frequency distribution. Let's assume the data is as follows (from the visible part, we'll list the numbers and count their frequencies):

Step 1: List the data points

First, let's extract the data from the given table (assuming the numbers are: 12, 14, 16, 20, 30, 25, 24, 12, 14, 16, 16, 20, 12, 14, 16, 15, 30, 12, 14, 16, 16, 20, 14, 15, 20, 24, 16, 16, 20, 19, 24, 16, 20, 30, 25, 30, 24). Wait, actually, let's count the number of data points. Let's list them properly:

First row: 12, 14, 16, 20, 30, 25, 24, 12, 14 (9 numbers)
Second row: 16, 16, 20, 12, 14, 16, 15, 30, 12 (9 numbers)
Third row: 14, 16, 16, 20, 14, 15, 20, 24, 14 (9 numbers)
Fourth row: 16, 16, 20, 19, 24, 16, 20, 30, 25 (9 numbers)
Fifth row: 30, 24, 16, 20, 34, 30, 25, 30, 24 (Wait, maybe a typo, but let's proceed with the visible numbers. Alternatively, maybe the data is about the number of days, so we can group them into classes. Let's assume we use the classes: 10 - 14, 15 - 19, 20 - 24, 25 - 29, 30 - 34.

Step 2: Count frequencies for each class
  • Class 10 - 14: Numbers between 10 (inclusive) and 14 (inclusive). Let's count: 12, 14, 12, 14, 12, 14, 12, 14, 14, 14, 14. Wait, maybe better to list all numbers:

From the first few rows:
12, 14, 16, 20, 30, 25, 24, 12, 14,
16, 16, 20, 12, 14, 16, 15, 30, 12,
14, 16, 16, 20, 14, 15, 20, 24, 14,
16, 16, 20, 19, 24, 16, 20, 30, 25,
30, 24, 16, 20, 34, 30, 25, 30, 24.

Now, count numbers in 10 - 14:
12 (3 times: first row: 12, 12; second row: 12; third row: none; fourth row: none; fifth row: none? Wait, first row: 12, 12 (two 12s), 14, 14 (two 14s). Second row: 12 (one 12), 14 (one 14). Third row: 14, 14, 14 (three 14s). Fourth row: none. Fifth row: none. So total 12s: 3, 14s: 2 + 1 + 3 = 6. Total in 10 - 14: 3 + 6 = 9? Wait, maybe I'm miscounting. Alternatively, let's use a better approach.

Alternatively, let's list all data points:

  1. 12
  2. 14
  3. 16
  4. 20
  5. 30
  6. 25
  7. 24
  8. 12
  9. 14
  10. 16
  11. 16
  12. 20
  13. 12
  14. 14
  15. 16
  16. 15
  17. 30
  18. 12
  19. 14
  20. 16
  21. 16
  22. 20
  23. 14
  24. 15
  25. 20
  26. 24
  27. 14
  28. 16
  29. 16
  30. 20
  31. 19
  32. 24
  33. 16
  34. 20
  35. 30
  36. 25
  37. 30
  38. 24
  39. 16
  40. 20
  41. 34
  42. 30
  43. 25
  44. 30
  45. 24

Now, let's count frequencies for each class (assuming classes are 10 - 14, 15 - 19, 20 - 24, 25 - 29, 30 - 34):

  • 10 - 14: Numbers 10,11,12,13,14. From the list: 12 (positions 1,8,13,18) → 4 times; 14 (positions 2,9,14,19,23,27) → 6 times. Total: 4 + 6 = 10.
  • 15 - 19: Numbers 15,16,17,18,19. 15 (positions 16,24) → 2; 16 (positions 3,10,11,15,20,21,28,29,33,39) → 10; 19 (position 31) → 1. Total: 2 + 10 + 1 = 13.
  • 20 - 24: Numbers 20,21,22,23,24. 20 (positions 4,12,22,25,30,34,40) → 7; 24 (positions 7,26,32,38,45) → 5. Total: 7 + 5 = 12.
  • 25 - 29: Numbers 25,26,27,28,29. 25 (positions 6,36,43) → 3. Total: 3.
  • 30 - 34: Numbers 30,31,32,33,34. 30 (positions 5,17,35,37,42,44) → 6; 34 (position 41) → 1. Total: 6 + 1 = 7.

Now, let's verify the total: 10 + 13 + 12 + 3 + 7 = 45, which matches the number of data points (45).

Step 3: Create the frequency distribution table
Class IntervalFrequency
15 - 1913
20 - 2412
25 - 293
30 - 347
Step 4: Draw the histogram (if needed)

The histogram would have the class intervals on the x - axis and the frequencies on the y - axis. Each bar's height corresponds to the frequency of the respect…

Answer:

The frequency distribution is as above. For example, the frequency of the class 20 - 24 is 12 (depending on the specific question, the answer would be adjusted. If it's about the frequency table, the table is as shown).