Question

for the trinomial $2x^2 + 1x - 6$, which pair of numbers multiplies to -12 and adds to 1? 6 and -2 4 and -3 -4 and 3 -6 and 2

Explanation:

Step1: Check 6 and -2

Multiply: $6\times(-2) = -12$
Add: $6 + (-2) = 4
eq 1$

Step2: Check 4 and -3

Multiply: $4\times(-3) = -12$
Add: $4 + (-3) = 1$

(We can stop here as we found the pair, but for completeness:

Step3: Check -4 and 3

Multiply: $-4\times3 = -12$
Add: $-4 + 3 = -1
eq 1$

Step4: Check -6 and 2

Multiply: $-6\times2 = -12$
Add: $-6 + 2 = -4
eq 1$)

Answer:

B. 4 and -3 (assuming the options are labeled as A: 6 and -2, B: 4 and -3, C: -4 and 3, D: -6 and 2; based on the check, 4 and -3 is the pair)