QUESTION IMAGE
Question
try it tomorrow!
given the situation and the horizontal table,
create a vertical table and write the equation for
the situation. then determine if the situation is
an additive or multiplicative relationship.
at a bookstore the total cost of 6 books is
$45.00. each book costs the same amount.
vertical table:
| process | ||
equation:
i know this relationship is \
bec
cost of books
\
Step1: Find cost per book
$\text{Cost per book} = \frac{\$45.00}{6} = \$7.50$
Step2: Build vertical table
List number of books, cost, and label columns.
| Process | ||
|---|---|---|
| 2 | 2 books cost | $\$15.00$ |
| 3 | 3 books cost | $\$22.50$ |
| 4 | 4 books cost | $\$30.00$ |
| 5 | 5 books cost | $\$37.50$ |
| 6 | 6 books cost | $\$45.00$ |
Step3: Write the equation
Let $C$ = total cost, $n$ = number of books.
$C = 7.50n$
Step4: Identify relationship type
Check if cost scales with number via multiplication.
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Vertical Table:
| Process | ||
|---|---|---|
| 2 | 2 books cost | $\$15.00$ |
| 3 | 3 books cost | $\$22.50$ |
| 4 | 4 books cost | $\$30.00$ |
| 5 | 5 books cost | $\$37.50$ |
| 6 | 6 books cost | $\$45.00$ |
Equation:
$C = 7.50n$ (where $C$ = total cost in dollars, $n$ = number of books)
Relationship:
multiplicative, because the total cost is equal to the number of books multiplied by a constant unit price ($\$7.50$), rather than adding a fixed value to the number of books.