Question

two right triangles, $\triangle abd$ and $\triangle acd$, were created from $\triangle abc$ by constructing $\overline{ad} \perp \overline{cb}$.
follow these steps to prove that $\frac{\sin(b)}{b} = \frac{\sin(c)}{c}$
√ 2. multiply both sides of the equation by $c$ and simplify. the equation $\sin(b) = \frac{h}{c}$ becomes $c\sin(b)=h$.
√ 3. for $\triangle acd$, $\sin(c) = \frac{h}{b}$

1. multiply both sides of the equation by $b$ and simplify. the equation $\sin(c) = \frac{h}{b}$ becomes

correct!
check

Explanation:

Step1: Multiply both sides by $b$

Multiply $\sin(C) = \frac{h}{b}$ by $b$:
$b \times \sin(C) = b \times \frac{h}{b}$

Step2: Simplify the equation

Cancel $b$ on the right-hand side:
$b\sin(C) = h$

Answer:

$b\sin(C) = h$