Question

unit conversion activity
→ use the conversion factors /equivalency shown below to complete the activity.
→ complete all work on this paper.
→ take a picture and submit it to the assignment post.

conversion factors / equivalency
mass (base unit - g) volume (base unit - l) distance (base unit - m)
1,000,000,000 g = 1 gg 1,000,000,000 l = 1 gl 1,000,000,000 m = 1 gm
1,000,000 g = 1mg 1,000,000 l = 1 ml 1,000,000 m = 1 mm
1,000 g = 1kg 1,000 l = 1 kl 1,000 m = 1 km
100 g = 1 hg 100 l = 1 hl 100 m = 1 hm
10 g = 1 dag 10 l = 1 dal 10 m = 1 dam
0.1 g = 1 dg 0.1 l = 1 dl 0.1 m = 1 dm
0.01 g = 1 cg 0.01 l = 1 cl 0.01 m = 1 cm
0.001 g = 1 mg 0.001 l = 1 ml 0.001 m = 1 mm
0.000001 g = 1 µg 0.000001 l = 1 µl 0.000001 m = 1 µm
0.000000001 g = 1 ng 0.000000001 l = 1 nl 0.000000001 m = 1 nm

part 1: find the equivalency using the image above then solve the problem.

1. equivalency: ____ cm = ____ m

74 cm x ____ = ____ m

1. equivalency: ____ kg = ____ g

0.0832 kg x ____ = ____ g

1. equivalency: ____ gl = ____ l

55.5 gl x ____ = ____ l

1. equivalency: ____ µm = ____ m

0.000952 m x ____ = ____ µm

1. equivalency: ____ ml = ____ l

41.0 ml x ____ = ____ l

Explanation:

Problem 2

Step1: Identify equivalency

From the mass conversion table, \(1\space kg = 1000\space g\). So the conversion factor is \(\frac{1000\space g}{1\space kg}\).

Step2: Perform conversion

Multiply \(0.0832\space kg\) by the conversion factor: \(0.0832\space kg\times\frac{1000\space g}{1\space kg}\)
The \(kg\) units cancel out, and we calculate \(0.0832\times1000 = 83.2\space g\).

Step1: Identify equivalency

From the volume conversion table, \(1\space GL = 1000000000\space L\) (or \(1\times10^{9}\space L\)). The conversion factor is \(\frac{1000000000\space L}{1\space GL}\).

Step2: Perform conversion

Multiply \(55.5\space GL\) by the conversion factor: \(55.5\space GL\times\frac{1000000000\space L}{1\space GL}\)
The \(GL\) units cancel out, and we calculate \(55.5\times1000000000 = 5.55\times10^{10}\space L\).

Step1: Identify equivalency

From the distance conversion table, \(1\space \mu m= 0.000001\space m\) (or \(1\times10^{- 6}\space m\)), so the reciprocal conversion factor (to convert \(m\) to \(\mu m\)) is \(\frac{1\space \mu m}{0.000001\space m}\) (or \(\frac{1\space \mu m}{1\times10^{-6}\space m}\)).

Step2: Perform conversion

Multiply \(0.000952\space m\) by the conversion factor: \(0.000952\space m\times\frac{1\space \mu m}{0.000001\space m}\)
The \(m\) units cancel out, and we calculate \(\frac{0.000952}{0.000001}=952\space \mu m\).

Answer:

Equivalency: \(1\) \(kg = 1000\) \(g\)
\(0.0832\space kg\times\frac{1000\space g}{1\space kg}= 83.2\space g\)

Problem 3