Question

6 from unit 1, lesson 13 the number of points jadas basketball team scored in their games have a mean of 44 and a standard deviation of about 15.7 points. interpret the mean and standard deviation in the context of jadas basketball team. 7 from unit 2, lesson 2 kirans family is having people over to watch a football game. they plan to serve sparkling water and pretzels. they are preparing 12 ounces of sparkling water and 3 ounces of pretzels per person. including kirans family, there will be 10 people at the gathering. a bottle of sparkling water contains 22 ounces and costs $1.50. a package of pretzels contains 16 ounces and costs $2.99. let n represent number of people watching the game, s represent the ounces of sparkling water, p represent the ounces of pretzels, b represent kirans budget in dollars. which equation best represents kirans budget? a. 12s + 3p = b b. 12·10 + 3·10 = b c. 1.50s + 2.99p = b d. 1.50·6 + 2.99·2 = b

Explanation:

Step1: Analyze water - cost relationship

A bottle of sparkling water contains 22 ounces and costs $1.50. We need to find out how many bottles are needed based on the total ounces of water required. For $s$ ounces of sparkling water, the number of bottles is not directly used in the budget - equation in a simple $12s$ way. The cost per ounce of sparkling water is $\frac{1.50}{22}$, but we can also think in terms of number of bottles. To get the cost of sparkling water, we consider the cost per bottle.

Step2: Analyze pretzel - cost relationship

A package of pretzels contains 16 ounces and costs $2.99. Similar to the water, for $p$ ounces of pretzels, the cost is based on the cost per package. The cost per ounce of pretzels is $\frac{2.99}{16}$, but again, we consider the cost per package for the budget equation.

Step3: Determine budget equation

The budget $b$ is composed of the cost of sparkling water and the cost of pretzels. The cost of sparkling water is based on the number of bottles (where each bottle costs $1.50$) and the cost of pretzels is based on the number of packages (where each package costs $2.99$). So the budget equation is $1.50s/22 + 2.99p/16=b$. But if we consider the cost per - unit item (bottle or package), we know that the cost of sparkling water is related to the number of bottles and the cost of pretzels is related to the number of packages. The correct way to write the budget equation in terms of the variables given is $1.50\times(\text{number of bottles})+2.99\times(\text{number of packages}) = b$. Since we are not given the number of bottles and packages in terms of $s$ and $p$ in a simple non - fractional way in the options, we note that we need to calculate based on cost per item. The budget is the sum of the cost of water and pretzels. Each bottle of water costs $1.50$ and each package of pretzels costs $2.99$. So the equation for the budget $b$ is $1.50s + 2.99p=b$ where $s$ and $p$ are related to the number of bottles and packages respectively in a more complex way considering the ounces per bottle/package.

Answer:

C. $1.50s + 2.99p = b$