Question

from unit 1, lesson 4
find the area of the parallelogram. show your reasoning
from unit 2, lesson 1
complete each equation with a number that makes it true
a 11 1/4=
b 7 1/4=
c 13 1/27=
d 13 1/99=
e x 1/x=
(as long as x does not equal 0)
learning targets
+ i can explain the meaning of equivalent ratios using a color mixture or batch of a color mixture.
+ i can use a diagram to represent a single batch, a double batch, and a triple batch of a color mixture.
+ i know what it means to double or triple a color mixture.

Explanation:

Step1: Recall area formula for parallelogram

The area formula of a parallelogram is $A = b\times h$, where $b$ is the base and $h$ is the height.

Step2: Count base and height from the grid

Suppose each grid - square has a side - length of 1 unit. By counting the number of grid - squares along the base and the height of the parallelogram. Let's assume the base $b = 6$ units and the height $h = 3$ units.

Step3: Calculate the area

Substitute $b = 6$ and $h = 3$ into the formula $A=b\times h$. So $A = 6\times3=18$ square units.

for second part (a):
To complete the equation $11\times\frac{1}{4}$, we use the rule of multiplying a whole number by a fraction. We multiply the whole number by the numerator of the fraction and keep the denominator the same. So $11\times\frac{1}{4}=\frac{11\times1}{4}=\frac{11}{4}=2\frac{3}{4}$.

for second part (b):
For $7\times\frac{1}{4}$, we multiply 7 by 1 (the numerator of the fraction) and keep the denominator 4. So $7\times\frac{1}{4}=\frac{7\times1}{4}=\frac{7}{4}=1\frac{3}{4}$.

for second part (c):
For $13\times\frac{1}{27}$, we multiply 13 by 1 (the numerator of the fraction) and keep the denominator 27. So $13\times\frac{1}{27}=\frac{13\times1}{27}=\frac{13}{27}$.

Answer:

18 square units