Question

use the diagram to complete the statement.
given $\triangle jkl$, $sin(38^{circ})$ equals
$circ$ $cos(38^{circ}).$
$circ$ $cos(52^{circ}).$
$circ$ $\tan(38^{circ}).$
$circ$ $\tan(52^{circ}).$

Explanation:

Step1: Recall co-function identity

For any angle $\theta$, $\sin(\theta) = \cos(90^\circ - \theta)$

Step2: Calculate complementary angle

$90^\circ - 38^\circ = 52^\circ$

Step3: Apply identity to the angle

$\sin(38^\circ) = \cos(52^\circ)$

Answer:

cos(52°)