Question

1. use the graph to find n(-1) and n(-1).

Explanation:

Step1: Find $n(-1)$

Locate $x = - 1$ on the $x$-axis. Then find the corresponding $y$-value on the graph of $y=n(x)$. We see that when $x=-1$, $y = - 4$. So $n(-1)=-4$.

Step2: Find $n'(-1)$

$n'(-1)$ is the slope of the tangent line to the graph of $y = n(x)$ at $x=-1$. The tangent - line to the graph of $y=n(x)$ at $x = - 1$ is a horizontal line. The slope of a horizontal line is $0$. So $n'(-1)=0$.

Answer:

$n(-1)=-4$, $n'(-1)=0$