QUESTION IMAGE
Question
- using the table below, determine how many valence electrons are in an atom of neon.
electron configurations and dot structures
| element | atomic number | electron configuration |
|---|---|---|
| beryllium | 4 | 1s²2s² |
| boron | 5 | 1s²2s²2p¹ |
| carbon | 6 | 1s²2s²2p² |
| nitrogen | 7 | 1s²2s²2p³ |
| oxygen | 8 | 1s²2s²2p⁴ |
| fluorine | 9 | 1s²2s²2p⁵ |
| neon | 10 | 1s²2s²2p⁶ |
Step1: Identify neon's electron configuration
Neon has an electron - configuration of $1s^{2}2s^{2}2p^{6}$.
Step2: Count the number of electrons
Sum the exponents of the electron - configuration. $2 + 2+6=10$.
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