Question

what is the average kinetic energy of the electrons ejected based on the incident light and the work function?
$w_{pt} = 1.0 \times 10^{-18}$ j
$e_{i} = 1.59 \times 10^{-18}$ j
$ke = \boldsymbol{?} \times 10^{\boldsymbol{?}}$ j

Explanation:

Step1: Recall photoelectric effect formula

The formula for the kinetic energy of ejected electrons is $KE = E_I - W_{Pt}$, where $E_I$ is the incident photon energy and $W_{Pt}$ is the work function.

Step2: Substitute given values

$KE = 1.59 \times 10^{-18}\ \text{J} - 1.0 \times 10^{-18}\ \text{J}$

Step3: Calculate the difference

$KE = 0.59 \times 10^{-18}\ \text{J}$

Step4: Adjust to standard form

Rewrite to match the required format: $KE = 5.9 \times 10^{-19}\ \text{J}$

Answer:

$KE = 5.9 \times 10^{-19}\ \text{J}$