QUESTION IMAGE
Question
what is the average time for the toy car to move 1.0 m on dirt?
○ 20.2 s
○ 24.4 s
○ 28.1 s
○ 60.7 s
time for toy car to travel 1.0 m on different surfaces
| surface | time (s) trial 1 | time (s) trial 2 | time (s) trial 3 |
|---|---|---|---|
| tile | 29.1 | 26.7 | 28.5 |
| cement | 25.5 | 23.4 | 24.2 |
Step1: Recall the formula for average
The formula for the average (mean) of a set of values is the sum of the values divided by the number of values. For the dirt surface, we have three trial times: \( t_1 = 20.0 \, \text{s} \), \( t_2 = 19.2 \, \text{s} \), and \( t_3 = 21.5 \, \text{s} \). The number of trials \( n = 3 \).
Step2: Calculate the sum of the times
First, we find the sum of the three times. So, \( \text{Sum} = t_1 + t_2 + t_3 = 20.0 + 19.2 + 21.5 \). Let's calculate that: \( 20.0+19.2 = 39.2 \), and then \( 39.2 + 21.5 = 60.7 \, \text{s} \).
Step3: Calculate the average
Now, we divide the sum by the number of trials to get the average. The average \( \bar{t} = \frac{\text{Sum}}{n} = \frac{60.7}{3} \). Let's compute that: \( \frac{60.7}{3} \approx 20.2 \, \text{s} \) (when rounded to one decimal place).
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20.2 s