Question

what is the correct chemical formula for the ionic compound tin(iv) oxide? 1 point sno sn₂o sno₂ sn₂o₄ in the ionic compound aluminum oxide (al₂o₃), the cation is aluminum and 1 point its charge is +3 false true which of the following chemical formulas represents the ionic compound formed between calcium (ca²⁺) and phosphate (po₄³⁻) using the criss - cross method? 1 point ca₂po₄ ca₃(po₄)₂ ca₄(po₄)₃ capo₄

Explanation:

Step1: Determine tin(IV) and oxygen ions

Tin(IV) has a charge of +4 ($Sn^{4 +}$), oxygen has a charge of - 2 ($O^{2-}$). To form a neutral compound, we need 2 oxygen atoms for every tin atom. So the formula of tin(IV) oxide is $SnO_{2}$.

Step2: Analyze aluminum oxide

In aluminum oxide ($Al_{2}O_{3}$), aluminum ($Al$) is the cation. Aluminum has a charge of +3 ($Al^{3+}$) and oxygen has a charge of - 2 ($O^{2 -}$). So the statement "In the ionic compound aluminum oxide ($Al_{2}O_{3}$), the cation is aluminum and its charge is +3" is True.

Step3: Use criss - cross method for calcium and phosphate

Calcium ($Ca^{2+}$) and phosphate ($PO_{4}^{3 -}$). Using the criss - cross method, we get $Ca_{3}(PO_{4})_{2}$.

Answer:

1. $SnO_{2}$
2. True
3. $Ca_{3}(PO_{4})_{2}$