Question

what element does this electron configuration represent?
$kr 5s^2 4d^{10} 5p^5$
br
i
xe
kr

Explanation:

1. First, find the atomic number of Kr (krypton), which is 36.
2. Add the electrons from the valence configuration: $2 + 10 + 5 = 17$.
3. Calculate the total atomic number: $36 + 17 = 53$.
4. The element with atomic number 53 is iodine (I).

Answer:

I. Iodine (I)