Question

1. what is the mole ratio of sodium carbonate to aluminum carbonate in the above reaction?

a. 1:3
b. 3:2
c. 2:3
d. 1:2
choose the option that best completes each sentence in the passage below.
the number of atoms on the reactant side is (the same as/different)
total mass of reactants is (the same as/different)
total amount of moles

Explanation:

Step1: Identify balanced reaction

The reaction between sodium carbonate ($\text{Na}_2\text{CO}_3$) and aluminum chloride ($\text{AlCl}_3$) is:
$$3\text{Na}_2\text{CO}_3 + 2\text{AlCl}_3 ightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{NaCl}$$

Step2: Extract mole ratio

From the balanced equation, the coefficient of $\text{Na}_2\text{CO}_3$ is 3, and the coefficient of $\text{Al}_2(\text{CO}_3)_3$ is 1. Wait, correction: the question asks for sodium carbonate to aluminum carbonate. From the balanced equation, 3 moles of $\text{Na}_2\text{CO}_3$ produce 1 mole of $\text{Al}_2(\text{CO}_3)_3$, so the ratio is 3:1? No, wait, no—wait, the reaction is:
$$3\text{Na}_2\text{CO}_3 + 2\text{AlCl}_3 ightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{NaCl}$$
So moles of $\text{Na}_2\text{CO}_3$ : moles of $\text{Al}_2(\text{CO}_3)_3$ = 3:1. But this is not an option. Wait, the question says "mole ratio of sodium carbonate to aluminum carbonate in the above reaction"—wait, maybe the reaction is the double displacement, but perhaps I misread the product. Wait, no, the options include 3:2, 2:3, 1:3, 1:2. Wait, maybe the question is reactant ratio? No, the question says sodium carbonate to aluminum carbonate. Wait, no—wait, maybe the reaction is between sodium carbonate and aluminum chloride to form aluminum carbonate, so the mole ratio of reactant $\text{Na}_2\text{CO}_3$ to product $\text{Al}_2(\text{CO}_3)_3$ is 3:1, but that's not an option. Wait, maybe the question is a typo, and it's sodium carbonate to aluminum chloride? Then it's 3:2, which is option B. But no, the question says aluminum carbonate. Wait, no—wait, let's recheck. Oh! Wait, maybe the question is asking for the ratio in the reaction where they are reactants? No, aluminum carbonate is insoluble, so it's a product. Wait, maybe the question is reversed? No, the question says sodium carbonate to aluminum carbonate. Wait, maybe I balanced the equation wrong. Let's balance again:
$\text{Na}_2\text{CO}_3 + \text{AlCl}_3
ightarrow \text{Al}_2(\text{CO}_3)_3 + \text{NaCl}$
Balance Al: 2 $\text{AlCl}_3$ on left, 1 $\text{Al}_2(\text{CO}_3)_3$ on right.
Balance CO$_3$: 3 $\text{Na}_2\text{CO}_3$ on left, 1 $\text{Al}_2(\text{CO}_3)_3$ on right.
Balance Na: 6 $\text{NaCl}$ on right.
Balance Cl: 6 Cl from 2 $\text{AlCl}_3$, 6 Cl from 6 $\text{NaCl}$. Correct.
So mole ratio of $\text{Na}_2\text{CO}_3$ to $\text{Al}_2(\text{CO}_3)_3$ is 3:1, which is not an option. Wait, maybe the question is asking for aluminum carbonate to sodium carbonate? That would be 1:3, option A. But the question says sodium carbonate to aluminum carbonate. Wait, maybe the reaction is different? Like, if it's a reaction where aluminum carbonate reacts with something to form sodium carbonate? No, the question says "in the above reaction"—the above reaction is probably the one with sodium carbonate and aluminum chloride. Wait, maybe the question has a mistake, but looking at the options, the only possible ratio from the balanced equation is 3:1, but since that's not an option, maybe I misread the question. Wait, the red writing says "Chloride"—maybe the question was supposed to be sodium carbonate to aluminum chloride? That would be 3:2, option B. But the question says aluminum carbonate. Wait, no—wait, maybe the question is asking for the ratio of sodium to aluminum in the carbonates? No, sodium carbonate is $\text{Na}_2\text{CO}_3$, aluminum carbonate is $\text{Al}_2(\text{CO}_3)_3$, so mole ratio of $\text{Na}_2\text{CO}_3$ to $\text{Al}_2(\text{CO}_3)_3$ is 1:1 for moles, but no. Wait, no, the question is mole ratio of the compounds. Wait, maybe the reaction is:
$\text{Na}_2\text{CO}_3 + \text{Al}_2(\text{CO}_3)_3
ightarrow$ no, that doesn't react. Wait, maybe the question is about the reaction between sodium hydroxide and aluminum carbonate? No, the red writing says Chloride. Oh! Wait, maybe the original question was mole ratio of sodium carbonate to aluminum chloride, and it was miswritten as aluminum carbonate. Then the ratio is 3:2, option B. But that's an assumption. Wait, no—wait, let's check the options again. The options are A.1:3, B.3:2, C.2:3, D.1:2. If the question is sodium carbonate to aluminum carbonate, the ratio is 3:1, which is not there. But if it's aluminum carbonate to sodium carbonate, it's 1:3, option A. But the question says sodium carbonate to aluminum carbonate. Wait, maybe I made a mistake in balancing. Let's try again:
Wait, maybe the reaction is $\text{Na}_2\text{CO}_3 + \text{Al}(\text{NO}_3)_3
ightarrow \text{Al}_2(\text{CO}_3)_3 + \text{NaNO}_3$
Balanced: $3\text{Na}_2\text{CO}_3 + 2\text{Al}(\text{NO}_3)_3
ightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{NaNO}_3$
Same ratio: 3:1. Still not an option. Wait, maybe the question is asking for the mole ratio of sodium to aluminum in the products? No, the question says sodium carbonate to aluminum carbonate. Wait, maybe the question is a trick question? No. Wait, maybe the question is about the ratio of carbonate ions? No, the question says the compounds. Wait, maybe the question is referring to the reaction where aluminum carbonate reacts with hydrochloric acid, and sodium carbonate reacts with hydrochloric acid? No, that doesn't make sense. Wait, the red writing says "Chloride"—so the original reaction is with aluminum chloride. So the question must have a typo, and it's asking for sodium carbonate to aluminum chloride, which is 3:2, option B. Alternatively, if it's aluminum carbonate to sodium chloride, no. Wait, no—wait, maybe the question is asking for the mole ratio of sodium carbonate to aluminum carbonate in a mixture? No, the question says "in the above reaction".

Wait, wait a second—maybe I misread the question. Let me re-read: "What is the mole ratio of sodium carbonate to aluminum carbonate in the above reaction?" Oh! Wait, maybe the reaction is the decomposition of aluminum carbonate? No, that forms aluminum oxide and carbon dioxide. No. Wait, maybe the reaction is sodium carbonate reacting with aluminum hydroxide? No, that doesn't form aluminum carbonate. Wait, aluminum carbonate is insoluble, so it's formed by double displacement. The only way to get aluminum carbonate is from a soluble aluminum salt and soluble carbonate salt. So sodium carbonate and aluminum chloride, which gives the balanced equation with 3 moles of sodium carbonate to 1 mole of aluminum carbonate. Since 3:1 is not an option, maybe the question is reversed, and it's aluminum carbonate to sodium carbonate, which is 1:3, option A. But the question says sodium carbonate to aluminum carbonate. Alternatively, maybe the question is asking for the ratio of moles of sodium in sodium carbonate to moles of aluminum in aluminum carbonate? No, that would be 2:2=1:1, which is not an option.

Wait, maybe the question has a mistake, but given the options, the most plausible intended question is mole ratio of sodium carbonate to aluminum chloride, which is 3:2, option B. Or maybe the question is asking for the ratio of aluminum carbonate to sodium carbonate, which is 1:3, option A. But since the question says sodium carbonate to aluminum carbonate, and 3:1 is not an option, maybe I made a mistake. Wait, no—wait, maybe the reaction is:
$2\text{AlCl}_3 + 3\text{Na}_2\text{CO}_3 + 3\text{H}_2\text{O}
ightarrow 2\text{Al(OH)}_3 + 6\text{NaCl} + 3\text{CO}_2$
In this case, there is no aluminum carbonate formed, it's a hydrolysis reaction. Oh! That's a possible reaction. So in this case, aluminum carbonate is not a product, so maybe the question is wrong. But the red writing says "Chloride", so the reactant is aluminum chloride.

Wait, maybe the question is from a context where the reaction is written as:
$\text{Na}_2\text{CO}_3 + \text{Al}_2(\text{CO}_3)_3
ightarrow \text{NaAl(CO}_3\text{)}_2$
Balanced: $2\text{Na}_2\text{CO}_3 + \text{Al}_2(\text{CO}_3)_3
ightarrow 4\text{NaAl(CO}_3\text{)}_2$
No, that's not balanced. Na would be 4 on left, 4 on right. Al would be 2 on left, 4 on right. No.

Wait, maybe the question is asking for the mole ratio of sodium carbonate to aluminum carbonate in terms of carbonate ions? No, sodium carbonate has 1 carbonate per mole, aluminum carbonate has 3 per mole, so ratio of carbonate ions would be 1:3, but that's not the compound ratio.

Wait, maybe the question is a mistake, but the most likely intended answer, given the options, is 3:2 if it's sodium carbonate to aluminum chloride, but the question says aluminum carbonate. Alternatively, maybe the question is asking for the ratio of moles of sodium carbonate needed to react with one mole of aluminum carbonate? But they don't react.

Wait, wait—maybe I misread the question. Is it aluminum carbonate or aluminum chloride? The red writing says "Chloride" over "carbonate", so maybe the original question was aluminum chloride, and it was corrected to carbonate, but that's a mistake. So if it's sodium carbonate to aluminum chloride, the ratio is 3:2, option B. That's the only option that makes sense with a balanced reaction involving sodium carbonate and aluminum chloride.

Answer:

B. 3:2