Question

what is the net ionic equation for the reaction between silver acetate and sodium phosphate? 3ag⁺ + 3c₂h₃o₂⁻ + 3na⁺ + po₄³⁻ → ag₃po₄ + 3na⁺ + 3c₂h₃o₂⁻ no reaction exists 3ag⁺ + po₄³⁻ → ag₃po₄ 3ag⁺ + 3na⁺ + po₄³⁻ → ag₃po₄ + 3na⁺

Explanation:

Step1: Identify reactants and their ions

Silver acetate (\(AgC_2H_3O_2\)) dissociates into \(Ag^+\) and \(C_2H_3O_2^-\), sodium phosphate (\(Na_3PO_4\)) dissociates into \(Na^+\) and \(PO_4^{3-}\). The total ionic equation would include all ions.

Step2: Identify spectator ions

Spectator ions are those that appear on both sides of the equation unchanged. Here, \(Na^+\) and \(C_2H_3O_2^-\) are spectator ions (they appear on both reactant and product sides in the first option).

Step3: Write net ionic equation

To get the net ionic equation, we remove the spectator ions. So we take the ions that form the precipitate ( \(Ag^+\) and \(PO_4^{3-}\)) and the precipitate (\(Ag_3PO_4\)). The correct net ionic equation is \(3Ag^+ + PO_4^{3-}
ightarrow Ag_3PO_4\) as we remove the spectator ions (\(Na^+\) and \(C_2H_3O_2^-\)) from the total ionic equation.

Answer:

3Ag⁺ + PO₄³⁻ → Ag₃PO₄