QUESTION IMAGE
Question
- what numbers would you subtract to get the answer of 16? (be sure to put a number in each blank. use 0 if there isnt a different number that should be put into the box.)(be sure to put a number in each blank. use 0 if there isnt a different number that should be put into the box.) 128 64 4 32 2 16 1 add the binary numbers and select the correct answer. 8 4 2 1 0 0 1 1 5 1 31 3
Step1: Solve Question 5
We need to find a number $X$ such that $X - Y = 16$, where $Y$ is a sum of the given place values (128, 64, 32, 16, 8, 4, 2, 1). To use the place values, we set up the equation for the largest possible $X$ using all place values, then find the subtraction:
Let $X = 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = 255$
We need $255 - Y = 16$, so $Y = 255 - 16 = 239$
Now convert 239 to binary (match the place values):
- $128$: $239 \geq 128$, so 1, $239-128=111$
- $64$: $111 \geq 64$, so 1, $111-64=47$
- $32$: $47 \geq 32$, so 1, $47-32=15$
- $16$: $15 < 16$, so 0
- $8$: $15 \geq 8$, so 1, $15-8=7$
- $4$: $7 \geq 4$, so 1, $7-4=3$
- $2$: $3 \geq 2$, so 1, $3-2=1$
- $1$: $1 \geq 1$, so 1
Step2: Solve Question 6
First, convert binary numbers to decimal:
- Binary 0011 (place values 4,2,1,0): $0*8 + 0*4 + 1*2 + 1*1 = 3$
- Binary 0100: $0*8 + 1*4 + 0*2 + 0*1 = 4$
Add them: $3 + 4 = 7$? No, wait, the table has place values 8,4,2,1:
First binary number (row 1): 0 (8), 0 (4), 1 (2), 1 (1) = $0+0+2+1=3$
Second binary number (row 2): 0 (8), 1 (4), 0 (2), 0 (1) = $0+4+0+0=4$
Sum: $3 + 4 = 7$
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Question 5 (filled table):
| 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 |
|---|
Question 6:
D. 7