Question

what is the ratio of al³⁺ ions to s²⁻ ions in a neutral compound?○ 1:1○ 2:1○ 2:3○ 3:2

Explanation:

$\text{S}^{2-}$ = $y$. Total negative charge = $2y$

Step3: Set charges equal for neutrality

$$3x = 2y$$

Step4: Solve for ratio $x:y$

$$\frac{x}{y} = \frac{2}{3} \implies x:y = 2:3$$

Answer:

$\text{S}^{2-}$ = $y$. Total negative charge = $2y$

Step3: Set charges equal for neutrality

$$3x = 2y$$

Step4: Solve for ratio $x:y$

$$\frac{x}{y} = \frac{2}{3} \implies x:y = 2:3$$