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7 if $f(x) = 7(x - 1) + 8$, what is the value of $f(1)$?

Question

7 if $f(x) = 7(x - 1) + 8$, what is the value of $f(1)$?

Explanation:

Step1: Substitute \( x = 1 \) into \( f(x) \)

We have the function \( f(x)=7(x - 1)+8 \). To find \( f(1) \), we replace \( x \) with \( 1 \) in the function. So we get \( f(1)=7(1 - 1)+8 \).

Step2: Simplify the expression

First, calculate the value inside the parentheses: \( 1-1 = 0 \). Then the expression becomes \( f(1)=7\times0 + 8 \). Since \( 7\times0=0 \), we have \( f(1)=0 + 8 \).

Step3: Calculate the final result

Adding \( 0 \) and \( 8 \) gives us \( f(1)=8 \).

Answer:

\( 8 \)