Question

when $f(x)=6x^2 - 3x + 4$, evaluate $f(-1)$
$f(-1)=square$
question help: video

Explanation:

Step1: Substitute x = -1 into f(x)

To evaluate \( f(-1) \) for the function \( f(x) = 6x^2 - 3x + 4 \), we substitute \( x = -1 \) into the function. So we get:
\( f(-1) = 6(-1)^2 - 3(-1) + 4 \)

Step2: Calculate each term

First, calculate \( (-1)^2 \), which is \( 1 \). Then:

• The first term: \( 6\times1 = 6 \)
• The second term: \( -3\times(-1) = 3 \)
• The third term: \( 4 \)

Now, add these results together: \( 6 + 3 + 4 \)

Step3: Sum the terms

\( 6 + 3 + 4 = 13 \)

Answer:

\( 13 \)