Question

when parker left his house this morning, his cell phone was 20% charged and it then started to lose 4% charge for each hour thereafter. write an equation for b, in terms of t, representing the charge remaining in parkers battery, as a percentage, t hours after parker left his house. number of hours since parker left his house percentage charge remaining on phone battery 0 1 2 3 answer you must answer all questions above in order to submit

Explanation:

Step1: Identify the initial charge

The initial charge when $t = 0$ is $20\%$.

Step2: Identify the rate of charge - loss

The phone loses $4\%$ charge per hour. So the amount of charge lost after $t$ hours is $4t\%$.

Step3: Form the equation

The remaining charge $B$ is the initial charge minus the charge lost. So $B=20 - 4t$.
Now, fill in the table:
When $t = 0$, $B=20-4\times0 = 20$.
When $t = 1$, $B=20-4\times1=16$.
When $t = 2$, $B=20 - 4\times2=12$.
When $t = 3$, $B=20-4\times3 = 8$.

Number of Hours Since Parker Left His House ($t$)	Percentage Charge Remaining on Phone Battery ($B$)
1	16
2	12
3	8

Answer:

The equation is $B = 20-4t$.